If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7k^2-35k=0
a = 7; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·7·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*7}=\frac{0}{14} =0 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*7}=\frac{70}{14} =5 $
| x-3/5=2.1/2 | | 5(k-4)=4-3 | | x.x.x.x=116 | | x-3/5=21/2 | | 3(2p+2.50=3150 | | 10b^2-51b+56=0 | | 0=40x+x^2-225 | | 81-j=54 | | 7k^2-35=0 | | 900-z=182 | | 3(x+7)-2x=12 | | u+1/8=3 | | 2s+s+6=39 | | 7(6+4m)=154 | | 28=2x(8+5) | | 63/r=7 | | 11q-4q-5q=14 | | a^2-28a+196=0 | | -13=5a-(-12) | | 2n-n+3n=20 | | 5(x-2)=2(x-3) | | 20u-11u-7u+u-2u=17 | | 2r−7=−1 | | x/2+10=10 | | 0.4(2x+1/2)=(0.2x+(-2)-4 | | 6/x+2=18/12 | | 3(-1)+1x=0 | | 10z-9z+3z-z=12 | | -8+6x=46 | | -(5x-5)-(8x-5)+7=-3(x-1)-(13x+4)+3 | | 12r-9r=15 | | 2x2+4x-6=0,x= |